1998 - WAEC Physics Past Questions and Answers - page 4

M = (\frac{V_H}{U_H} = \frac{300}{7.62})

= 39.3

U = (\frac{V}{M} = \frac{1000}{39.3}) = 25.44

(\frac{1}{f} = \frac{I}{U} + \frac{I}{V} = \frac{I}{25.44} = \frac{I}{1000} = \frac{1025.44}{25440})

f = (\frac{25440}{1025.44} = 24.8)

f = (\frac{v}{2(l_2 - l_1)} = \frac{340}{2(0.37 - 0.12)} = \frac{34}{0.5}) = 680

f (\alpha) (\sqrt{T})

(\frac{f_1}{f_2} = \sqrt{\frac{T_1}{T_2}})

(\frac{250}{350} = \sqrt{\frac{10}{T_2}})

(\frac{5}{7} = \sqrt{\frac{10}{T_2}})

(\frac{25}{49} = \frac{10}{T_2})

T² = (\frac{49 \times 10}{25} = 19.6)

(\lambda) = (\frac{v}{f} = \frac{352}{256})

= 1.38

(_an_w = \frac{\lambda_a}{\lambda_w})

(\frac{4}{3} = \frac{\lambda_a}{\lambda})

(\lambda_w = \frac{v}{f})

= (\frac{3.0 \times 10^8}{5.0 \times 10^{14}} = 0.6 \times 10^{-6})

(\lambda_w = \frac{3}{4} \lambda_a = \frac{3}{4} \times 0.6 \times 10^{-6})

= 4.5 x 10^-7m

(\frac{1}{6}F_E = F_{MOON})

F_E = R = 6F_m

= 6 x 6 = 36N

I = (\frac{V}{R} = \frac{0.9}{3} = 3)

r = (\frac{E}{I} = \frac{1.5}{0.3} = 5)