2001 - JAMB Mathematics Past Questions and Answers - page 1

Hint: Use BODMAS, in other words, do multiplication of the second and the last first before subtracting value obtained from the first.

HINT:

(\frac{(p^{2} - q^{2})}{2pq}=\frac{(1+\sqrt{2})^{2}}{2((1+\sqrt{2})(1-\sqrt{2}))})

Use difference of two squares to expand the bracket and reduce to (\frac{2(2\sqrt{2})}{-2} = -2\sqrt{2})

Total cost = N(250,000 + 70,000) = N320,000

Selling price = N400,000 (given)

Gain = SP - CP = N(400,000 - 320,000) = N80,000

Gain % = gain/CP x 100 = (80,000/320,000) x 100

Gain % = 25%

Principal, P = Amount, A - Interest, I.

A = P + I

I = (P.T.R)/100 = (P x 5 x 2)/100 = 10P/100 = P/10

But A = P + I,

=> 5500 = P + (P/10)

=> 55000 = 10P + P

=> 55000 = 11P

Thus P = 55000/11 = N5,000

(0.14² x 0.275) 7(0.02) = (0.14 x 0.14 x 0.275)/(7 x 0.02) = (0.14 x 0.14 x 0.275)/(0.14)

=0.14 x 0.275 = 0.0385 Approx. 0.039

(y = px^{2}+q\y = 2x^{2}-1\Rightarrow px^{2}+q=2x^{2}-1\px^{2}=2x^{2}-1-q\p=\frac{(2x^{2}-q-1)}{x^{2}}\At\hspace{1mm}x=2\p=\frac{2(2^{2})-1-q)}{2^{2}}\p=\frac{(8-1-q)}{4}=\frac{7-q}{4})

Hint: Sketch the inequality graph for the 3 conditions given and read out your points from the co-ordinates.