2023 - JAMB Physics Past Questions and Answers - page 2

The absolute pressure (\(P_{\text{abs}}\)) in the tank can be calculated using the equation \(P_{\text{abs}} = P_{\text{atm}} + \rho gh\), where:

- \(P_{\text{atm}}\) is the atmospheric pressure (given as \(101,325 \, \text{Pa}\)),
- \(\rho\) is the density of mercury (\(13,600 \, \text{kg/m}^3\)),
- \(g\) is the acceleration due to gravity (\(9.8 \, \text{m/s}^2\)),
- \(h\) is the height difference of the mercury column (\(0.25 \, \text{m}\)).

Substituting the values:

\[
P_{\text{abs}} = 101,325 + 13,600 \times 9.8 \times 0.25 \\
P_{\text{abs}} = 101,325 + 33,320 \\
P_{\text{abs}} = 134,645 \, \text{Pa}
\]

Therefore, the correct answer is: \(134,645 \, \text{Pa}\).

The Bohr model of the atom, proposed by Niels Bohr in 1913, describes electrons as orbiting the nucleus in specific energy levels or shells. According to this model, electrons occupy quantized orbits, and each orbit is associated with a specific energy level. Electrons can jump from one energy level to another by absorbing or emitting energy in discrete packets or quanta. The Bohr model was an improvement over the earlier Rutherford model and provided a better explanation for the spectral lines of hydrogen.

The horizontal range (R) of a projectile launched at an angle can be calculated using the formula:

\[ R = \frac{v^2 \sin(2\theta)}{g} \]

where:
- \( v \) is the initial speed of the projectile,
- \( \theta \) is the launch angle,
- \( g \) is the acceleration due to gravity.

In this case, \( v = 75 \, \text{m/s} \), \( \theta = 22^\circ \), and \( g = 10 \, \text{m/s}^2 \).

\[ R = \frac{(75)^2 \sin(2 \times 22^\circ)}{10} \]

Calculating this expression yields approximately 391 m.

Surface tension is a measure of the force that tends to pull adjacent parts of a liquid's surface together, minimizing the surface area. Mercury has a relatively high surface tension compared to the other liquids listed, making it the correct answer in this case.

The charge (\(Q\)) on each plate of the capacitor can be calculated using the formula \(Q = CV\), where:

- \(C\) is the capacitance,
- \(V\) is the voltage.

The capacitance (\(C\)) for a parallel plate capacitor with air as the dielectric is given by \(C = \frac{\varepsilon_0 A}{d}\), where:

- \(\varepsilon_0\) is the vacuum permittivity (\(8.85 \times 10^{-12} \, \text{F/m}\)),
- \(A\) is the area of the plates (\(0.8 \, \text{m}^2\)),
- \(d\) is the separation between the plates (\(0.02 \, \text{m}\)).

Let's substitute the values:

\[
C = \frac{(8.85 \times 10^{-12} \, \text{F/m})(0.8 \, \text{m}^2)}{0.02 \, \text{m}} = 3.54 \times 10^{-10} \, \text{F}
\]

Now, calculate the charge (\(Q\)):

\[
Q = CV = (3.54 \times 10^{-10} \, \text{F})(120 \, \text{V}) = 4.25 \times 10^{-8} \, \text{C}
\]

Convert the charge to nanocoulombs:

\[
4.25 \times 10^{-8} \, \text{C} = 42.5 \, \text{nC}
\]

Therefore, the correct answer is: \(42.5 \, \text{nC}\).

The formation of a rainbow involves refraction, dispersion, and total internal reflection. Here's a more accurate summary:

When sunlight shines on a water droplet, the light undergoes refraction as it enters the droplet. The different colours of light are dispersed due to the varying wavelengths. Finally, total internal reflection occurs inside the droplet, leading to the formation of a rainbow.

The rate at which energy is transferred by conduction from the surface to the bottom of the swimming pool (\(\frac{q}{t}\)) can be calculated using the formula:

\[
\frac{q}{t} = K \cdot A \cdot \frac{\Delta \theta}{L}
\]

where:
- \(K\) is the thermal conductivity of water (\(0.6071 \, \text{W/m} \cdot \text{K}\)),
- \(A\) is the surface area of the pool (\(620 \, \text{m}^2\)),
- \(\Delta \theta\) is the temperature difference (\(25^\circ \text{C} - 15^\circ \text{C} = 10^\circ \text{C}\)),
- \(L\) is the depth of the pool (\(1.5 \, \text{m}\)).

Substitute the values:

\[
\frac{q}{t} = 0.6071 \times 620 \times \frac{10}{1.5} = 2509.35 \, \text{W}
\]

Convert the result to kilowatts (\(\text{kW}\)):

\[
\frac{2509.35 \, \text{W}}{1000} = 2.50935 \, \text{kW}
\]

Approximately, the rate of energy transfer is \(2.5 \, \text{kW}\), so the correct option is: \(2.5 \, \text{kW}\).

The relationship between the number of turns in the primary (Np) and secondary (Ns) windings of a transformer, and the primary (Vp) and secondary (Vs) voltages, is given by: Vp / Vs = Np / Ns We are given: Vp = 2.2 kV = 2200 V Vs = 110 V Ns = 25 turns We need to find Np. Rearranging the formula to solve for Np: Np = (Vp / Vs) * Ns Substituting the given values: Np = (2200 V / 110 V) * 25 Np = 20 * 25 Np = 500 turns Therefore, the primary winding has 500 turns.

Insulators are materials that do not conduct electricity well. Rubber is known for its high electrical resistance, making it a good insulator. On the other hand, silver, copper, and water are conductors of electricity.

Diffraction is the bending of waves around the corners of an obstacle or through an aperture.