1990 - WAEC Mathematics Past Questions and Answers - page 5

41

The bearing of a point X from a point Y is 074°. What is the bearing of Y from X?

A
106o
B
146o
C
164o
D
254o
correct option: d

< YXS = 74° (alternate angles, N\(_1\) S\(_1\) // N\(_2\) S\(_2\))

N\(_2\) E\(_2\) S\(_2\) = 180°

\(\therefore\) Bearing of Y from X = 180° + 74°

= 254°

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42

The annual salary of Mr. Johnson Mohammed for 1989 was N12,000.00. He spent this on agriculture projects, education of his children, food items, saving , maintenance and miscellaneous items as shown in the pie chart

How much money did he invest in agriculture?

A
N1,200.00
B
N1,440.00
C
N2,000.00
D
N2,910.00
correct option: e

Agric project = \(\frac{120}{360} \times N12,000.00\)

= \(N4,000.00\)

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43

The table shows that the amount of money (in naira)collected through voluntary donations in a secondary school. What is the mode?

A
N3
B
N6
C
N9
D
N12
correct option: d

Mode = 12

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44

The table shows that the amount of money (in naira)collected through voluntary donations in a secondary school.

What is the median of distribution
A
N3.00
B
N9.00
C
N12.00
D
N15.00
correct option: c
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45

Two groups of male students cast their votes on a particular proposal. The result are as follows:

  In favor Against
Group A 128 32
Group B 96 48

If a student in favor of the proposal is selected for a post, what is the probability that he is from group A?

A
8/19
B
16/35
C
10/19
D
4/7
correct option: a

Probability that a student in favor is group A

= \(\frac{128}{128 + 32 + 96 + 48}\)

= \(\frac{128}{304}\)

= \(\frac{8}{19}\)

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46

Two groups of male students cast their vote on a particular proposal. The results are as follows:

  In favor Against
Group A 128 32
Group B 96 48

If a student is chosen at random, what is probability that he is against the proposal?

A
3/19
B
4/19
C
5/19
D
9/19
correct option: c

Probability that the student is against the proposal

= \(\frac{32 + 48}{128 + 32 + 96 + 48}\)

= \(\frac{80}{304}\)

= \(\frac{5}{19}\)

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47

The annual salary of Mr. Johnson Mohammed for 1989 was N12,000.00. He spent this on agriculture projects, education of his children, food items, saving , maintenance and miscellaneous items as shown in the pie chart

How much did he spend on food items?

A
N9,700.00
B
N6,700.00
C
N2,000.00
D
N4,000.00
correct option: e

Degree for food items = 360° - (120° + 80° + 43° + 30° + 18°)

= 360° - 291°

= 69°

∴∴ Amount spent on food items = \(\frac{69}{360}\)×12,000.00

= N2300.00

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