2011 - WAEC Mathematics Past Questions and Answers - page 1

D14.95 = N112.00

D1.00 = (\frac{N112}{D14.95} \times) D1.00

= 7.49

(\frac{3}{5})(2x - 1) = (\frac{1}{4})(5x - 3)

(\frac{6x}{5} - \frac{3}{5} = \frac{5x}{4} - \frac{3}{4})

(\frac{6x}{5} - \frac{5x}{4} = \frac{3}{5} - \frac{3}{4})

(\frac{24x - 25x}{20} = \frac{12 - 15}{20})

(\frac{-x}{20} = \frac{-3}{20})

-20x = -60

x = (\frac{-60}{-20})

x = 3

cos x^o = (\frac{1}{r}); (\sqrt{r^2 - 1})

By Pythagoras r² = 1² + x² - 1

x = (\sqrt{r^2 - 1})

tan x^o = (\sqrt{r^2 - 1})

= (\sqrt{r^2 - 1})

3x - 2y = 7; Solve by elimination method

x + 2y = -3

3x - 2y = 7.....(i)

-3x + 6y = -9.....(ii)

-8y = 16

y = (\frac{16}{-8} = -2)

Put y = -2 into equation (i); 3x - 2y = 7

3x - 2(-2) = 7

3x + 4 = 7

3x = 7 - 4

3x = 3

x = (\frac{3}{3}) = 1

set = 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15

multiple of 3 = 6, 9, 12, 15

multiple of 4 = 4, 8, 12

Prob(multiple of 3 or 4) = Prob(multiple of 3) + pro(multiple of 4)

= (\frac{4}{12} + \frac{3}{12} = \frac{7}{2})

mn - nq - n² + mq

mn - n² - nq + mq

(mn - n) - (nq - mq)

n(m - n) - q(n - m)

= n - q

Volume of cylinder = (\pi r^2 h)

= (\frac{22}{7} \times 14^2) x 14 x 18 = 22 x 28 x 18

= 11088cm³

1000cm³ = (\frac{1}{1000}) x 11088cm³

= 11.088

= 11

Each interior angle = (\frac{360^o}{n})

45^o = (\frac{360^o}{n})

45^on = 360^o

n = (\frac{360^o}{45})

= 8

A prism has 3 rectangular faces and 2 triangular faces and 2 rectangular faces = 10(3 + 4 + 5) = 120

Area of triangular faces = (\sqrt{s(s - a) (s - b) (s - c)})

where s = (\frac{a + b + c}{2})

= (\frac{3 + 4 + 5}{2})

= (\frac{12}{2})

= 6

Area of (\bigtriangleup) = (\sqrt{6(6 - 30(6 - 4)(6 - 5)})

= (\sqrt{6 \times 3 \times 2 \times 1}) = 6

Area of triangle faces = 2 x 6 = 12cm²

Total surface area = Area of rectangular face + Area of (\bigtriangleup) = 120 + 12

= 132cm²