2004 - JAMB Mathematics Past Questions and Answers - page 5
41
A farmer planted 5000 grains of maize and harvested 5000 cobs, each bearing 500 grains. What is the ratio of the number of grains sowed to the number harvested?
A
1 : 250 000
B
1 : 25 000
C
1 : 500
D
1 : 5 000
42
The shadow of a pole 5√3m high is 5m. Find the angle of elevation of the sun.
A
45o
B
75o
C
30o
D
60o
43
A
{(x,y) : y - 3x < -6}
B
{(x,y) : y + 3x < 6}
C
{(x,y) : y + 3x < -6}
D
{(x,y) : y - 3x < 6}
correct option: b
Coordinates of the line are (x1 y1)(0,2) respectively and (x2 y2)(2,0) respectively
Gradient (m) of the line = (y2 - y1) / (x2 - x1) = (0-6) / (2-0) = -6/2
= -3
Equation of the line y-y1 = m(x-x1)
y - 6 = -3(x - 0)
y - 6 = -3x
y + 3x = 6
inequality; from the y axis, the shaded region is below the line
∴ y + 3x ∠ 6 and line is a broken line
Users' Answers & CommentsGradient (m) of the line = (y2 - y1) / (x2 - x1) = (0-6) / (2-0) = -6/2
= -3
Equation of the line y-y1 = m(x-x1)
y - 6 = -3(x - 0)
y - 6 = -3x
y + 3x = 6
inequality; from the y axis, the shaded region is below the line
∴ y + 3x ∠ 6 and line is a broken line
44
PQRSTV is a regular polygon of side 7 cm inscribed in a circle. Find the circumference of the circle PQRSTV.
A
56 cm
B
22 cm
C
42 cm
D
44 cm
correct option: d
| Each interior Angle of the polygon = | (n-2) | 180 |
| _n |
| = | (6-2) | 180 |
| _6 |
= 4 x 30
= 120o
i.e ∠PQR = 120o ∴ RQD = 120/2 = 60o also
∴ Δ QOR is equilateral Δ ∴ QO = 7cm
∴ PO = QO = RO ...... = 7cm radius of the circumference of the circle = 2πr
= 2 x 22/7 x 7/1
= 44 cm
45
A
Po \(\cap\)(Q \(\cap\) R)
B
P \(\cap\) Q
C
Po\(\cup\)(Q\(\cap\)R)
D
Po \(\cup\)(Q \(\cup\)R)
correct option: a
Users' Answers & Comments46
A
{(x, y) : y + 3x < 6}
B
{(x , y) : y + 3x < -6}
C
{(x, y) : y - 3x < 6}
D
{(x, y) : y - 3x < 6}
correct option: a
when x = 0, y = 0 \(\to\) (0, 6)
when y = 0, x = 2 \(\to\) (2, 0)
y + 3x < 6
Users' Answers & Commentswhen y = 0, x = 2 \(\to\) (2, 0)
y + 3x < 6
47
A
35o
B
40o
C
45o
D
55o
correct option: a
< PRS = 20o + 35o = 55o
< POS = 2 < PRS
2 x 55o = 10o
< OPS = < PSO = x
In \(\bigtriangleup\)POS
OP = OS(radii)
\(\bigtriangleup\)POS is an isosceles
2x + 110o = 180o
2x = 180o - 110o = 70o
x = \(\frac{70^o}{2}\)
= 35o
Users' Answers & Comments< POS = 2 < PRS
2 x 55o = 10o
< OPS = < PSO = x
In \(\bigtriangleup\)POS
OP = OS(radii)
\(\bigtriangleup\)POS is an isosceles
2x + 110o = 180o
2x = 180o - 110o = 70o
x = \(\frac{70^o}{2}\)
= 35o
48
A
24cm2
B
48cm2
C
60cm2
D
72cm2
correct option: a
Users' Answers & Comments49
A
9000 tonnes
B
6000 tonnes
C
1500 tonnes
D
1200tonnes
correct option: d
beans angle = 360o - (60o + 90o + 150o)
360o - 300o = 60o
150o - 3000 tonnes
60o - \(\frac{60}{150} \times 3000\) tonnes
= 1,200 tonnes
Users' Answers & Comments360o - 300o = 60o
150o - 3000 tonnes
60o - \(\frac{60}{150} \times 3000\) tonnes
= 1,200 tonnes
50
A
68%
B
28%
C
17%
D
8%
correct option: b
\(\begin{array}{c|c} \text{class-marks(x)} & \text{(freq. (f)} & \text{cum. freq.}\\hline 9 & &3.....3\14 & & 6....3 + 6 = 9\ 19 & & 9.....9 + 9 = 18\ 24 & & 3.....18 + 3 = 21\ 29 & & 2.....21 + 2 = 23\ 34 & & 2.....23 + 2 = 25\ & & 25\end{array}\)
% of students scoring more than 20 marks
= \(\frac{7}{25}\) x 100% = 28%
Users' Answers & Comments% of students scoring more than 20 marks
= \(\frac{7}{25}\) x 100% = 28%