2008 - JAMB Mathematics Past Questions and Answers - page 10
91
A
12.5cm2
B
75.0cm2
C
78.5cm2
D
84.8cm2
correct option: d
Area of semicircle + Area of rectangle
A = \(\frac{1}{2} \pi r^2\) + LB
A = \(\frac{1}{2} \times \frac{22}{77} \times (\frac{5}{2})^2 + (15 \times 5)\)
= \(\frac{1}{2}\times \frac{22}{7} \times \frac{25}{4} + 75\)
A = \(\frac{275}{28} + \frac{75}{1}\)
\(\frac{275 + 2100}{28} = \frac{2375}{28}\)
A = 84.8cm2
Users' Answers & CommentsA = \(\frac{1}{2} \pi r^2\) + LB
A = \(\frac{1}{2} \times \frac{22}{77} \times (\frac{5}{2})^2 + (15 \times 5)\)
= \(\frac{1}{2}\times \frac{22}{7} \times \frac{25}{4} + 75\)
A = \(\frac{275}{28} + \frac{75}{1}\)
\(\frac{275 + 2100}{28} = \frac{2375}{28}\)
A = 84.8cm2
92
A
\(\frac{1}{4}\)
B
\(\frac{1}{3}\)
C
\(\frac{2}{3}\)
D
\(\frac{3}{4}\)
correct option: a
\(\frac{\text{least}}{\text{most}} = \frac{3}{12} = \frac{1}{4}\)
Users' Answers & Comments