2008 - JAMB Mathematics Past Questions and Answers - page 7

4x - 7 (\leq) 3x

4x - 3x (\leq) 7

x (\leq) 7

ii. 3x - 4 (\leq) 4x

3x - 4x (\leq) 4

-x (\leq) -4

-4 (\leq) x (\leq) 7

x² - 5x + 6 (\geq) 0

x² - 2x - 3x + 6 (\geq) 0

x(x - 2) - 3(x - 2) (\geq) 0

(x - 2) (x - 3) (\geq) 0

x (\geq) 2 or (\geq) 3

x (\leq) 2 (\geq)

In = a + (n - 1)d

24 = a + (5 - 1)d

24 = a + 4d.......(i)

96 = a + (11 - 1)d

96 = a + 10d.......(ii)

a = 24 - 4d.......(iii)

96 = 24 - 4d + 10d

96 = 24 + 6d

96 - 24 = 6d

72 = 6d

d = (\frac{72}{6})

d = 12

a = 24 - 4d

a = 24 - 4 x 12

a = 24 - 48

a = -24

a (\ast) b = b (\ast) a

x (\ast) y = y (\ast) x

2x - 3y + 2 (\neq) 2y - 3y - 3x + 2

2 (\ast) 3 = 2(2) -3(3) + 2

= 4 - 9 + 2

= -3

1 (\ast) 2 = 2(1) - 3(2) + 2

= 2 - 6 + 2

= 2 - 6 + 2

= -2

m (\Delta) n = m + n + mn

m (\Delta) e = e (\Delta) m = m

m (\Delta) e = m

m + e + me = m

e + me = m - m

e + me = 0

e(1 + m) = 0

e = (\frac{0}{1 + m}) = 0

(\begin{pmatrix} 1 & 0 \ -1 & -1\ 2 & 2 \end{pmatrix}) + (\begin{pmatrix} x & 1 \ -1 & 0\ y & -2 \end{pmatrix}) = (\begin{pmatrix} -2 & 1 \ -2 & -1\ -30 & 0 \end{pmatrix})

therefore, (x, y) = (-3, -5) respectively

-2p + r = 1.......(i)

2p + 3r = 0.......(ii)

r - 1 + 2p ........(iii)

2p + 3(1 + 2p) = 0

2p + 3(1 + 2p) = 0

2p + 3 + 6p = 0

3 - 8p = 0 (\to) 8p = 3

p = (\frac{3}{8})

6 = 1 - 2 (\frac{3}{8})

= 1 - (\frac{6}{8})

(\frac{8 - 6}{8}) = (\frac{2}{8})

= (\frac{1}{4})

Equilateral are equal in sides and angle

180^o = 60^o + 60^o + 60^o

(\theta) = 60^o

r = 1

h = 14

(\pi) = (\frac{22}{7})

A = (\pi)r²h

A = (\frac{22}{7}) x 1² x 14

A = 44m²

A = 44 x 10 litres

A = 440 litres

let (6, 2) be represented as (x₁, y₁) and (4, 2) be (x₂, y₂)

p(6, 2) R(4, 2)

m.p = ((\frac{x_1 + x_2}{2})) ((\frac{y_1 + y_2}{2}))

= ((\frac{6 + 4}{2}) , (\frac{2 + 2}{2}))

= ((\frac{10}{2}),(\frac{4}{2}))

= (5, 2)