2010 - WAEC Mathematics Past Questions and Answers - page 1
1
Simplify 0.000215 x 0.000028 and express your answer in standard form
A
6.03 x 109
B
6.02 x 109
C
6.03 x 10-9
D
6.02 x 10-9
correct option: d
0.000215215 x 0.000028
= 215 x 10-4 x 28 x 10-4
= 215 x 28 x 10-6-6
= 6020 x 10-12
= 6.020 x 103 x 10-12
= 6.02 x 103 - 12
= 6.02 x 10-9
Users' Answers & Comments= 215 x 10-4 x 28 x 10-4
= 215 x 28 x 10-6-6
= 6020 x 10-12
= 6.020 x 103 x 10-12
= 6.02 x 103 - 12
= 6.02 x 10-9
2
Factorize: x + y - ax = ay
A
(x - y)(1 - a)
B
(x + y)(1 + a)
C
(x + y)(1 - a)
D
(x - y)(1 + a)
3
A car uses one litre of petrol for every 14km. If one of petrol cost N63.00, how far can the car go with N900.00 worth of petrol?
A
420km
B
405km
C
210km
D
200km
correct option: d
1 litre = N63.00
xlitres = N900.00
x x N63 = N900 x 1 litre
x = \(\frac{900}{63} \times litre\)
x = \(\frac{100}{7}\) litres
Also, 1 litre = 14km
\(\frac{100}{7}\) = y
y x 1 litre = \(\frac{100litre}{7}\) x 14km
y = 20km
Users' Answers & Commentsxlitres = N900.00
x x N63 = N900 x 1 litre
x = \(\frac{900}{63} \times litre\)
x = \(\frac{100}{7}\) litres
Also, 1 litre = 14km
\(\frac{100}{7}\) = y
y x 1 litre = \(\frac{100litre}{7}\) x 14km
y = 20km
4
Correct 0.002473 to 3 significant figure
A
0.002
B
0.0024
C
0.00247
D
0.0025
correct option: c
Users' Answers & Comments5
Simplify 1\(\frac{1}{2} + 2\frac{1}{3} \times \frac{3}{4} - \frac{1}{2}\)
A
-2\(\frac{1}{3}\)
B
-2\(\frac{1}{4}\)
C
2\(\frac{1}{8}\)
D
2\(\frac{3}{4}\)
correct option: d
1\(\frac{1}{2} + 2\frac{1}{3} \times \frac{3}{4} - \frac{1}{2}\)
\(\frac{3}{2} + \frac{7}{3} \times \frac{3}{4} - \frac{1}{2} = \frac{3}{2} + \frac{7}{4} - \frac{1}{2}\)
= \(\frac{6 + 7 - 2}{4} = \frac{11}{4}\)
= 2\(\frac{3}{4}\)
Users' Answers & Comments\(\frac{3}{2} + \frac{7}{3} \times \frac{3}{4} - \frac{1}{2} = \frac{3}{2} + \frac{7}{4} - \frac{1}{2}\)
= \(\frac{6 + 7 - 2}{4} = \frac{11}{4}\)
= 2\(\frac{3}{4}\)
6
The sum of 2 consecutive whole numbers is \(\frac{5}{6}\) of their product, find the numbers
A
3, 4
B
1, 2
C
2, 3
D
0, 1
correct option: c
Let the no. be x and x + 1
x + (x + 1) = \(\frac{5}{6}\) of x(x + 1)
2x + 1 = \(\frac{5}{6}\) x(x + 1)
6(2x + 1) = 5x2 + 5x
12x + 6 = 5x2 + 5x
5x2 + 5x - 12x - 6 = 0
5x2 - 7x - 6 = 0
5x2 - 10x + 3x - 6 = 0
5x(x - 2) + 3(x - 2) = 0
(5x + 3)(x - 2) = 0
(5x + 3)(x - 2) = 0
(5x + 3) = 0
x - 2 = 0
for (5x + 3) = 0
5x = -3
x = \(\frac{-3}{5}\) (Imposible since x is a whole number)
x - 2 = 0
x = 2
x = \(\frac{-3}{5}\)(Impossible since x is a whole number)
x - 2 = 0
x = 2
The numbers are x = 2
x + 1 = 2 + 1
= 3
Users' Answers & Commentsx + (x + 1) = \(\frac{5}{6}\) of x(x + 1)
2x + 1 = \(\frac{5}{6}\) x(x + 1)
6(2x + 1) = 5x2 + 5x
12x + 6 = 5x2 + 5x
5x2 + 5x - 12x - 6 = 0
5x2 - 7x - 6 = 0
5x2 - 10x + 3x - 6 = 0
5x(x - 2) + 3(x - 2) = 0
(5x + 3)(x - 2) = 0
(5x + 3)(x - 2) = 0
(5x + 3) = 0
x - 2 = 0
for (5x + 3) = 0
5x = -3
x = \(\frac{-3}{5}\) (Imposible since x is a whole number)
x - 2 = 0
x = 2
x = \(\frac{-3}{5}\)(Impossible since x is a whole number)
x - 2 = 0
x = 2
The numbers are x = 2
x + 1 = 2 + 1
= 3
7
A casting is made up of Copper and Zinc. If 65% of the casting is Zinc and there are 147g of Copper. What is the mass of the casting?
A
320g
B
420g
C
520g
D
620g
correct option: b
%Zinc + %Copper = 100%
65% + %Copper = 100%
%Copper = 100% - 65% = 35%
%Copper = \(\frac{\text{Mass of % Copper}}{\text{Mass of Casting}}\) x 100%
Mass of Casting = \(\frac{147}{35}\) x 100%
= 420g
Users' Answers & Comments65% + %Copper = 100%
%Copper = 100% - 65% = 35%
%Copper = \(\frac{\text{Mass of % Copper}}{\text{Mass of Casting}}\) x 100%
Mass of Casting = \(\frac{147}{35}\) x 100%
= 420g
8
Given that P = {x : 1 \(\leq x \leq 6\)}, and Q = {x : 2 \(\leq x \leq 10\)} where x is an integer. Find n(P \(\cap\))
A
4
B
6
C
8
D
10
correct option: a
P = {1, 2, 3, 4, 5, 6}; Q = {3, 4, 5, 6, 7, 8, 9}
P \(\cap\) Q) = {2, 4, 5, 6}
n(P \(\cap\) Q) = 4
Users' Answers & CommentsP \(\cap\) Q) = {2, 4, 5, 6}
n(P \(\cap\) Q) = 4
9
The sum of 6 and one-third of x is one more than twice x, find x
A
x = 7
B
x = 5
C
x = 3
D
x = 2
correct option: c
6 = \(\frac{1}{3}x\) = 1 + 2x
6 = 1 = \(\frac{2x}{1} - \frac{x}{3}\)
5 = \(\frac{6x - x}{3} = \frac{5x}{3}\)
5 = \(\frac{5x}{3}\)
3 x 5 = 5x
15 = 5x
x = \(\frac{15}{5}\)
= 3
Users' Answers & Comments6 = 1 = \(\frac{2x}{1} - \frac{x}{3}\)
5 = \(\frac{6x - x}{3} = \frac{5x}{3}\)
5 = \(\frac{5x}{3}\)
3 x 5 = 5x
15 = 5x
x = \(\frac{15}{5}\)
= 3
10
Given that = {x: -2 < x \(\leq\) 9}, where x is an integer what is n(T)?
A
9
B
10
C
11
D
12