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1992 - JAMB Mathematics Past Questions and Answers - page 3

21
p = \(\begin{vmatrix} x & 3 & 0 \ 2 & y & 3\ 4 & 2 & 4 \end{vmatrix}\)

Q = (\begin{vmatrix} x & 2 & z \ 3 & y & 2\ 0 & 3 & z \end{vmatrix}) Where pT is the transpose P calculate /pT/ when x = 0, y = 1 and z = 2

A
48
B
24
C
-24
D
-48
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22

p = (\begin{vmatrix} x & 3 & 0 \ 2 & y & 3\ 4 & 2 & 4 \end{vmatrix})

Q = (\begin{vmatrix} x & 2 & z \ 3 & y & 2\ 0 & 3 & z \end{vmatrix})

PQ is equivalent to

A
PPT
B
pp-1
C
qp
D
pp
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23

If the angles of quadrilateral are (P + 10)o(2P - 30)o(3P + 20)o and 4po, find p

A
63
B
40
C
36
D
28
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24

Determine the distance on the earth's surface between two town P (latoN, Long 20oN) and Q(Lat 60oN, Long 25oW) (Radius of the earth = 6400km)

A
\(\frac{800\pi}{9}\)km
B
\(\frac{800\sqrt{3\pi}}{9}\)km
C
800\(\pi\) km
D
800\(\sqrt{3\pi}\) km
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25

If in the diagram, FG is parallel to KM, find the value of x

A
75o
B
95o
C
105o
D
125o
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26

x is a point due east of point Y on a coast Z is another point on the coast but 63m due south of y. If the distance ZX is 12Km. Calculate the bearing of Z from X

A
240o
B
210o
C
150o
D
60o
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27

The locus of a point which is equidistant from two given fixed points is the

A
perpendicular bisector of the straight line joining them
B
parallel line to the straight line joining them
C
transverse to the straight line joining them
D
angle bisector of 90o which the straight line joining them makes with the horizontal
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28

What is the perpendicular distance of a point (2, 3) from the line 2x - 4y + 3 = 0?

A
\(\frac{\sqrt{5}}{2}\)
B
\(\frac{\sqrt{5}}{20}\)
C
\(\frac{5}{\sqrt{13}}\)
D
6
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29

find then equation line through (5, 7) parallel to the line 7x + 5y = 12

A
5x + 7y = 120
B
7x + 5y = 70
C
x + y = 7
D
15x + 17y = 90
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30

Given that (\theta) is an acute angle and sin (\theta) = (\frac{m}{n}), find cos (\theta)

A
\(\frac{\sqrt{n^2 - m^2}{m}\)
B
\(\frac{\sqrt{(n + m)(n - m)}{n}\)
C
\(\frac{m}{\sqrt{n^2 - m^2}\)
D
\(\sqrt{\frac{n}{n^2 - m^2}}\)
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